The mass of a non-hollow cube made of some substance is 2.4 kg. What will be the mass of this cube

The mass of a non-hollow cube made of some substance is 2.4 kg. What will be the mass of this cube if the length of its edge is reduced by 2 times?

Problem data: m1 (mass of the original cube) = 2.4 kg; a1 (edge length of the original cube) = 2a ^ 2 (edge length of the resulting cube).
1) Change in the volume of the cube: V2 / V1 = a2 ^ 3 / a13 = (0.5a1 ^ 3) / a1 ^ 3 = 1/8.
2) The mass of the resulting cube: m2 / m1 = V2 * ρ / (V1 * ρ) = V2 / V1 = V1 / 8V1 = 1/8, whence m2 = m1 / 8 = 2.4 / 8 = 0.3 kg ( 300 g).
Answer: The resulting cube will have a mass of 300 grams.