From a height of 10 m from the surface of the earth, a ball was thrown vertically upward at a speed of 20 m / s.
September 30, 2021 | education
| From a height of 10 m from the surface of the earth, a ball was thrown vertically upward at a speed of 20 m / s. At what distance from the ground will the ball be located in 2 seconds?
Distance the ball will be at:
S = h + V0 * t + a * t² / 2, where h is the initial height of the ball above the ground (h = 10 m), V0 is the initial velocity of the ball when thrown (V0 = 20 m / s), t is the time of the ball in flight (t = 2 s), a is the acceleration with which the ball moves (a = -g = -10 m / s², the movement is equally slow).
S = h + V0 * t – g * t² / 2.
Let’s do the calculation:
S = 10 + 20 * 2 – 10 * 2² / 2 = 10 + 40 – 20 = 30 m.
Answer: After 2 seconds, the ball will be 30 m above the ground.
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