The body moving evenly passes 2.5 seconds in five seconds after which it begins to move uniformly
September 23, 2021 | education
| The body moving evenly passes 2.5 seconds in five seconds after which it begins to move uniformly and within 5 seconds it passes 150 cm. With what acceleration did the body begin to move?
Given: t1 (duration of uniform movement) = 5 s; S1 (first path) = 2.5 m; t2 (duration of accelerated movement) = 5 s; S2 (second path) = 150 cm (in SI S2 = 1.5 m).
1) Constant speed of the taken body on the first path (initial speed on the second path): V1 = S1 / t1 = 2.5 / 5 = 0.5 m / s.
2) Acceleration of the body on the second path: S2 = V1 * t2 + a * t2 ^ 2/2, whence a = (S2 – V1 * t2) * 2 / t2 ^ 2 = (1.5 – 0.5 * 5) * 2/5 ^ 2 = (1.5 – 2.5) * 2/25 = -0.08 m / s2.
Answer: Acceleration is -0.08 m / s2.
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